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rosijanka [135]
3 years ago
12

hey everyone!! im just doing a checkup, how is everyone doing? like with your mental health. if you need any help with anything

im here <3
Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

I could be better, I failed this quarter in ELA and Math I feel like my dad hates me. How are you?

Step-by-step explanation:

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On a coordinate plane, line P Q goes through (negative 3, negative 3) and (3, negative 1). Point R is at (1, 1).
olga55 [171]

Answer:

0, 2/3

Step-by-step explanation:

Its the only one that make sense.

hope thats right

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What is the sum of all the whole numbers from 1 to 1000?
Katen [24]

Answer:

So there are 500 pairs of numbers that have a sum of 1001. Thus, the sum of numbers from 1 to 1000 is 500*1001 = 500,500.

Step-by-step explanation:

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3 years ago
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Rudiy27

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The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0
4 years ago
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In a given year, the population of Metro City is 7420, and the population is decreasing by 152 people per year. The population o
Anit [1.1K]

Answer:

The correct option is D.

Step-by-step explanation:

Let <em>x</em> denote the years.

The information provided is:

  • The population of Metro City is 7420.
  • The population is decreasing by 152 people per year.
  • The population of Smallville is consistently 1200 less than half of Metro City.

From the provided data derive the equation for the population of Smallville <em>x</em> years after as follows:

Y = [\frac{1}{2}\cdot (7420-152x)]-1200

The population of Smallville is 2282 after <em>x</em> years.

Compute the value of <em>x</em> as follows:

2282= [\frac{1}{2}\cdot (7420-152x)]-1200

\frac{7420-152x}{2}=2282+1200\\\\7420-152x=3482\times 2\\\\152x=7420-6964\\\\152x=456\\\\x=3

Thus, the time it will take for Smallville's population to reach 2282 is 3 years.

The correct option is D.

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4 years ago
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