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serg [7]
3 years ago
15

3. Could a 5 x 8 matrix have dim Col A 6 and dim Nul A - 2? Justify your answer. (Hint: Think about the possible pivot rows and

columns
Mathematics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

No

Step-by-step explanation:

A 5x8 matrix A represents a linear transformation between the vector space \mathbb{R}^8 and \mathbb{R}^5. Remeber that the columns of A generate the image of the linear transformation, which is a vector subspace of \mathbb{R}^5. Therefore, \dim \text{Col}A \leq 5, which is the dimension of the the total space.

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g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th
xxTIMURxx [149]

Answer:

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Sampling with replacement:

I consider a success choosing a black ball, so p = \frac{50}{150+50} = \frac{50}{200} = 0.25

We want 2 black balls and 2 white, 2 + 2 = 4, so n = 4, and we want P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so N = 200

Sample of 4, so n = 4

50 are black, so k = 50

We want P(X = 2).

P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

3 0
2 years ago
Which answered describe the shape below ?
Vitek1552 [10]

Answer:

B. Trapezoid

Step-by-step explanation:

Trapezoid  is a quadrilateral with only one pair of parallel sides, so it's "B".

5 0
3 years ago
Which values are solutions to the inequality below? Check all that apply
azamat
A, e, and f! hope it helps
5 0
2 years ago
Read 2 more answers
Jamal hiked on two trails.The first trail was 5 1/3 miles long,and the second trail was 1 3/4 times as long as the first trail.H
olya-2409 [2.1K]
The answer Is 9 1/3.
4 0
3 years ago
Helppppppppppppfpvkvkkvmvmvmvmvmvmgmvm
zepelin [54]

Answer:

I think it's 2.56

you convert the 8 percent to a decimal and then you times it to 3.20

3.20×.8=2.56 (it's wrong)

6 0
3 years ago
Read 2 more answers
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