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vlabodo [156]
2 years ago
10

This app is amazing! Please help I’m really confused!

Mathematics
2 answers:
RideAnS [48]2 years ago
7 0
The answer to the question

Alex777 [14]2 years ago
3 0

Answer:

7(x+3)

Step-by-step explanation:

7x+21

7x = 7*x

21 = 7*3

We can factor out a 7 from both terms.  What remains is what is inside the parentheses

7(x+3)

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I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
Read 2 more answers
Just having lil problem with this math problem if anyone can help me please solving. thanks
Cloud [144]
1-2 is right
3 you have to draw a shape and then put 3 lines then shade in one
number 4 you have to draw a shape again but put 8 lines through then shade 1
5 your answer is 1/8
6 your answer is 1/4
7 you have to draw a shape again draw 3 line in the shape then shade 1 and your fraction is 1/3
7 0
3 years ago
I need help , help me I'll help you back at the same time
iragen [17]
All that you are doing is trying to fiigure out the Frequency of all the tally marks!!

4 0
3 years ago
Find x if AB = 9, BC = 2x - 5,<br> and AC = x + 9
Oxana [17]

Answer:

x = 5

Step-by-step explanation:

Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:

AB + BC = AC

Now, using the given values, we can substitute in for the equation and solve for x:

AB + BC = AC

9 + 2x - 5 = x + 9

2x + 4 = x + 9

x = 5

Thus, we have found that for these sets of equations for these line segments, our value for x should be 5.

Cheers.

5 0
3 years ago
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ASAP!!! Graphic DesignWorks purchased $15,000 worth of computers in 2005.
sergeinik [125]

Answer:

D. $3000

Step-by-step explanation:

Just did the test

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3 years ago
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