This: >(Greater than) and <(less than)
7+8 is the answer
But it can also be 11
Answer: 195.5 or 12 7/32
Step-by-step explanation:
There is no letter tetha in the table so I use α instead. However it is not sence to final result.
The expression is:
(sinα+cosα)/(cosα*(1-cosα))
Lets divide the nominator and denominator by cosα
(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=
=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)
As known cos²α=1-sin²α (divide by cos²α both sides of equation)
cos²a/cos²α=1/cos²α-sin²α/cos²α
1=1/cos²α-tg²α
1/cos²α=1+tg²α
cos²α=1/(1+tg²α)
cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=
=+-sqrt(225/289)=+-15/17 (2)
Substitute in (1) cosα by (2):
1st use cosα=15/17
1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5
2-nd use cosα=-15/17
2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32
Answer:
-4.01, -4, -7
Step-by-step explanation:
equation:
-x + 6 ≥ 10
substitute each number for x
- (-3.9) + 6 ≥ 10 = (negatives cancel each other out) 3.9 + 6 = 9.9 ≥ 10 (incorrect)
-4 + 6 ≥ 10 = 2 ≥ 10 (incorrect)
- (-4.01) + 6 ≥ 10 = (negatives cancel each other out) 10.01 ≥ 10 (correct)
- (-4) + 6 ≥ 10 = (negatives cancel each other out) 10 ≥ 10 (correct)
-4.01 + 6 ≥ = 1.99 ≥ 10 (incorrect)
-3.9 + 6 ≥ 10 = 2.1 ≥ 10 (incorrect)
-0 + 6 ≥ 10 = 6 ≥ 10 (incorrect)
- (-7) + 6 ≥ 10 = (negatives cancel each other out) 11 ≥ 10 (correct)
