1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maks197457 [2]
3 years ago
11

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

7×103)=2.7×103(7.5×106)−(2.5×106)=5×100
Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

let me edit your question as:

Which two equations are true?

<u>Eq1:</u>

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

<u>Eq2:</u>

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

<u>Eq3:</u>

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

<u>Eq1:</u>

(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\

<u>Eq2:</u>

<u></u>6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1<u></u>

<u>Eq3:</u>

2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>

<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>

You might be interested in
It's #25 guys. Show your work!
Ronch [10]
y+8 = \frac{1}{2}(x-7) is equivalent to <span>y-(-8) = \frac{1}{2}(x-7)

That is in the form </span><span>y-y_{1} = m(x-x_{1}) which is point slope form

In this case,

m = 1/2 is the slope
(x1,y1) = (7,-8) is the point the line goes through</span>
6 0
3 years ago
HELP me on this please
Rzqust [24]

Answer:

angle FEA is 100°

angle AEC is 20°

angle CEG is 60°

Step-by-step explanation:

angle AEC=angle DEB=20°

angle AEG=angle FED=80°

80°-20°=60°; angle CEG=60°

angle FEA+angle AEC+ angle CEG=180°

angle FEA=100°

6 0
2 years ago
A football team lost a total of 2 1/2 yards in 5 plays. What was the average change in yardage per play?
leonid [27]

Answer:

0.5 yards

Step-by-step explanation:

average change in yardage per play = total yards / number of plays

2.5 yards / 5 = 0.5 yards

6 0
2 years ago
Look at the triangles shown below.
Sophie [7]

Answer:

Variant c

Step-by-step explanation:

c²=4*9

c=6

You can apply phyphagor

b²=6²+9²=36+81=117

3 \sqrt{13}

4 0
2 years ago
A doctor has invented a relaxation method that he
likoan [24]

Answer:

Exam score

Step-by-step explanation:

The response variable also known as the d pendent variable, is simply the variable we intend to measure based in a set of variables (independent variables or explanatory variables) which might cause it to change. For instance, the scenario above aims to look into how a certain relaxation method will affect the exam score, here, the variable we intend to measure is the response variable which is exam score. The exam score is affected by the impact the relaxation method has on the student, hence, the relaxation method is the independent or explanatory variable.

4 0
2 years ago
Other questions:
  • Simplify the equation
    13·1 answer
  • Write the number of feet as a number of yards when necessary round your answer to the nearest tenths of a week 89 feet
    11·1 answer
  • P= $600<br> R= 12.5%<br> T= 2 years<br> Answer?
    6·2 answers
  • How do you solve 6 7/8 + 1 2/8 =
    10·1 answer
  • What does "⋅" mean in math..
    5·2 answers
  • How many 45. angles would it take to turn in a complete circle
    12·2 answers
  • 16^2+8^2= <br> Show what you did
    8·2 answers
  • 7.4x-y=-252,12.1x-y=-231
    7·1 answer
  • Please help quick im using a big attack
    10·1 answer
  • NEED HELP ASAP
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!