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3 years ago

Which expression can be used to find the surface area of the following rectangular prism?

Mathematics

2 answers:

enyata [817]3 years ago

7 0

Answer:

option A

Step-by-step explanation:

Here we can see that , the dimensions of the prism ( cuboid ) is 3 × 5 × 6 . If a cuboid has dimensions of l × b × h , then its TSA is ,

⇒ TSA = 2(lb + bh + hl)

⇒ TSA = 2[ (3)(5)+(5)(6)+(6)(3) ]

⇒ TSA = 2 [ 15 + 30 + 18 ]

⇒ TSA = 15 + 15 + 30 + 30 + 18 + 18

Hence the option A is correct .

<h3>Hence option (A) is correct. </h3>

worty [1.4K]3 years ago

5 0

A is the correct answer

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Hi! Please without looking it up I am doing my writing and speaking test for Spanish and I'm trying to figure out what is "Then"

inysia [295]

Answer:

The sentance you but then would be than which would be Hay más mesas en la cocina que en mi habitación but the word then would be entonces and example sentance is entonces iré allí which is then i will go over there

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Two consecutive integers have a sum of 75. Find the integers.

Pie

Answer:

37 and 38

Step-by-step explanation:

let the consecutive integers be x-1 and x

If their sum is 75

x-1+x = 75

2x - 1 = 75

2x = 75+1

2x = 76

x = 76/2

x = 38

First integer = x - 1

First integer = 38-1 = 37

Second integer is 38

Hence the integers are 37 and 38

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3 years ago

Daisy wants to make 12 clay animals to give away as Valentines gifts. Each animal she makes uses 1/2 of a stick of clay. How muc

Free_Kalibri [48]

Answer:
Daisy will need 6 sticks of clay

4 0

2 years ago

Read 2 more answers

HELP

Aleks [24]

Answer:

c) 6

Step-by-step explanation:

This is a straight-forward application of the Law of Cosines:

... a² = b² + c² -2bc·cos(A)

... a² = 8² +11² -2·8·11·cos(32.2°) ≈ 64 +121 -176·0.8462

... a² ≈ 36.07000

... a ≈ 6.00583

The best choice is c) 6.

3 0

3 years ago

4 Tan A/1-Tan^4=Tan2A + Sin2A

Eva8 [605]

tan(2A) + sin(2A) = sin(2A)/cos(2A) + sin(2A)

• rewrite tan = sin/cos

… = 1/cos(2A) (sin(2A) + sin(2A) cos(2A))

• expand the functions of 2A using the double angle identities

… = 2/(2 cos²(A) - 1) (sin(A) cos(A) + sin(A) cos(A) (cos²(A) - sin²(A)))

• factor out sin(A) cos(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (1 + cos²(A) - sin²(A))

• simplify the last factor using the Pythagorean identity, 1 - sin²(A) = cos²(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (2 cos²(A))

• rearrange terms in the product

… = 2 sin(A) cos(A) (2 cos²(A))/(2 cos²(A) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(A)

… = 4 sin(A) cos(A) / (2 - 1/cos²(A))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(A) cos(A) / (2 - sec²(A))

• divide through again by cos²(A)

… = (4 sin(A)/cos(A)) / (2/cos²(A) - sec²(A)/cos²(A))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(A) / (2 sec²(A) - sec⁴(A))

• factor out sec²(A) in the denominator

… = 4 tan(A) / (sec²(A) (2 - sec²(A)))

• rewrite using the Pythagorean identity, sec²(A) = 1 + tan²(A)

… = 4 tan(A) / ((1 + tan²(A)) (2 - (1 + tan²(A))))

• simplify

… = 4 tan(A) / ((1 + tan²(A)) (1 - tan²(A)))

• condense the denominator as the difference of squares

… = 4 tan(A) / (1 - tan⁴(A))

(Note that some of these steps are optional or can be done simultaneously)

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3 years ago