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Roman55 [17]
3 years ago
15

Which expression can be used to find the surface area of the following rectangular prism?

Mathematics
2 answers:
enyata [817]3 years ago
7 0

Answer:

option A

Step-by-step explanation:

Here we can see that , the dimensions of the prism ( cuboid ) is 3 × 5 × 6 . If a cuboid has dimensions of l × b × h , then its TSA is ,

⇒ TSA = 2(lb + bh + hl)

⇒ TSA = 2[ (3)(5)+(5)(6)+(6)(3) ]

⇒ TSA = 2 [ 15 + 30 + 18 ]

⇒ TSA = 15 + 15 + 30 + 30 + 18 + 18

Hence the option A is correct .

<h3><u>Hence</u><u> </u><u>option</u><u> </u><u>(</u><u>A</u><u>)</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u>. </u></h3>
worty [1.4K]3 years ago
5 0
A is the correct answer
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inysia [295]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Two consecutive integers have a sum of 75. Find the integers.
Pie

Answer:

37 and 38

Step-by-step explanation:

let the consecutive integers be x-1 and x

If their sum is 75

x-1+x = 75

2x - 1 = 75

2x = 75+1

2x = 76

x = 76/2

x = 38

First integer = x - 1

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Second integer is 38

Hence the integers are 37 and 38

7 0
3 years ago
Daisy wants to make 12 clay animals to give away as Valentines gifts. Each animal she makes uses 1/2 of a stick of clay. How muc
Free_Kalibri [48]
Answer:
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4 0
2 years ago
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HELP
Aleks [24]

Answer:

c) 6

Step-by-step explanation:

This is a straight-forward application of the Law of Cosines:

... a² = b² + c² -2bc·cos(A)

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3 0
3 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
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