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Anvisha [2.4K]
3 years ago
13

WILL GIVE BRAINLIEST... make me laugh

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

What did an iphone spit the apple?

Step-by-step explanation:

So it could become an andriod AHAHAHHAHAHAAAAA

amm18123 years ago
6 0

I'm not funny but I'll tell you about one embarrassing moment I had in middle school.

I was at the school gym and I was to be using the treadmill. I left my treadmill to go grab a bottle of water and I came back heading over to my treadmill. I didn't see the ground until I noticed that I stepped on somebody else's treadmill that was going at full speed.

I fell and fell and I couldn't use my hands to stand up because the treadmill kept moving. It was started to hurt because I was getting burns from my hands, arms, and face.

The coaches tried to grab me and I could hear people laughing.

My friends told me I looked like a stray dog that was going to be ran over...yeah.

The next day some boys picked at me the other day.

The worst day of my life.

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The number of books checked out from the library varies directly with the number of book reports assigned. there were 3375 books
yan [13]
3375/225=15
13500/15=900 books
The answer is D
5 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
F(m)=m^4-6m^3+5m^2+10m-4 at m=4
Alexandra [31]

Answer:

F(m) = -12

Step-by-step explanation:

Given the function:

F(m)=m^{4}-6m^{3}+5m^{2}+10m-4

When m = 4, we substitute the variable 'm' for the number 4:

F(m)=4^{4}-6(4)^{3}+5(4)^{2}+10(4)-4

F(m) = 256 - 384 + 80 + 40 - 4

F(m) = -12

6 0
3 years ago
job starting salary of 81,000 and gets a 2% raise every year.what is the expected salary after the eight year ? please explain h
Neporo4naja [7]

Answer:

hell have 120,000

Step-by-step explanation:


8 0
3 years ago
Sunhee had four plastic shapes a square, a circle, and a pentagon in how many ways can she line up the four shapes of the circle
julsineya [31]

Answer:

only three shapes are mentioned.

But anyhow, 4 shapes allow the following reasoning...

you can start lining up with any of the for shapes, so you have 4 possibilities, for the second position you have 3 possibilities, for the third 2 and for the last only 1.

so 4*3*2*1= 24 possible ways

but with the added rule to keep the circle and the square apart, we have to reduce the number.

by the same step-by-step reasoning we get

4 possibilities for the 1st item

only 2 possibilities for the 2nd item

(if 1st is square or circle, the other one's not an option, if it's not we have to choose one of them to not place them both at point 3 and 4)

only 1 choice for the 3rd item

(reasoning as above, if 2nd is square or circle, we have to the only other, if it isn't, we can put it here at 3rd position)

plus scenarios where either square or circle are on 1st point, the other's on 4th.

I guess that makes 14 possible arrangements

5 0
3 years ago
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