Answer:
5.60 pounds each
Step-by-step explanation:
This is the dry mixture problem.
Let x = the number of pounds of the first type of candy
Therefore, number of pounds of second type of candy = 10-x
Value of first candy + value of second candy = value of mixture
Value of any candy = cost per pound of candy * weight of candy
Thus:
4x + 6(10 - x) = 5.60(10)
4x + 60 - 6x = 56
-2x + 60 = 56
-2x = -4
x = -4/-2
x = 2
Therefore, the number of pounds of first type of candy = 2 pounds
The number of pounds of second type of candy = 10 - 2 = 8 pounds
Check
$4(2) + $6(8) =
8 + 48 = $5.60(10)
$56 = $56
It depends on the shape it may be rotation
Cos = adjacent / hypotenuse
cos B = 4/5
B = cos^-1 (4/5)
B = 36.869897....
B = 36.87° (nearest hundredth)
Angle B = 36.87°.
I hope this helps you
Volume =pi.r^2.h
Volume =3,14.8^2.10
Volume =31,4.64
Volume =200,96
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
