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Kryger [21]
3 years ago
11

What’s the value of X

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

I believe it is 65°.

Step-by-step explanation:

All angles of a triangle add up to 180, so you would add the measurements that you do know and subtract it from 180. If I am wrong please let me know :)

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1. 12(x−4)= <br><br><br><br>2. −8(y+12)=<br><br><br><br>3. −(x−11)=
Natali5045456 [20]

Answer:

12x-48

-8y-96

-x+11

Step-by-step explanation:

8 0
4 years ago
Simplify 2x + 5(2x - 3)
WARRIOR [948]

Answer:12x-15

Step-by-step explanation:2x+5(2x-3)

2x+10x-15

12x-15

8 0
3 years ago
Researchers once surveyed students on which superpower they would most like to have. The following two-way table displays data f
GenaCL600 [577]

Answer:

The percent of students in the sample who were male is 48%.

Step-by-step explanation:

The complete question is:

Researchers once surveyed 100 students on which superpower they would most like to have. The following two-way table displays data for the sample of students who responded to the survey.

Superpower    Male    Female    TOTAL

Fly                      26           12           38

Invisibility           12           32           44

Other                  10            8            18

TOTAL               48           52          100

What percent of students in the sample were male?

Solution:

The probability of an event <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The number of males in the sample is, <em>n</em> (M) = 48.

Total number of students, <em>N</em> = 100.

Compute the probability of selecting a male student as follows:

P(M)=\frac{n(M)}{N}\\

          =\frac{48}{100}\\\\=0.48

Then the percent of students in the sample who were male is:

\text{Percent of Males}=P(M)\times 100\%

                          =0.48\times 100\%\\\\=48\%

Thus, the percent of students in the sample who were male is 48%.

4 0
3 years ago
Read 2 more answers
Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b
Elenna [48]

Answer:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Step-by-step explanation:

We want to verify the identity:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }

Collect LCM

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }

We simplify the RHS to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}

We rationalize to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}

We expand to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}

Factor negative one in the denominator:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}

Apply the Pythagoras Property to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}

Simplify to get:

\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}

Or

\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}

Divide both the numerator and denominator by sin x

\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}

This finally gives:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

8 0
3 years ago
Heidi grew her hair out for many years. Her hair was 12/10 of a meter long. She donated her hair by cutting off 5/6 of a meter.
coldgirl [10]

Answer:

0.37 meters.

Step-by-step explanation:

12/10 of 1 meter = 1.2meters

5/6 of 1 meter = 0.8333333333 meters.

1.2 meters - 0.833333333 meters = 0.366666667 meters.

~0.37 meters

Please give brainliest if I am correct, if I am not; sorry about that.

8 0
3 years ago
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