If one-sixth of a certain number is four more than one-twelfth the number, the required number will be 48.
Let the unknown number be 'a'
One-sixth of the number is expressed as 1/6 a ..... 1
One-twelfth the number is also expressed as 1/12 a
Four more than one-twelfth the number will be written as:
1/12 a + 4 .... 2
Equating 1 and 2 will give:
1/6 a = 1/12 a + 4
a/6 = a/12 + 4
Collect the like terms
Find the LCM
Cross multiply
a = 12×4
a = 48
This shows that the required number is 48
Learn more on equations here: brainly.com/question/14034270
Answer:
Step-by-step explanation:
To move all the constants to the right side: Subtract 0.4 from both sides
-9x = 3.6
To isolate the variable: Divide both sides of equation by -9
x = -3.6/9
Solution of the equation: -0.4
Answer:
x = 14
Step-by-step explanation:
∠A = (8x – 12) and ∠B = (6x + 14)
∠A = ∠B because they are vertical angles
then:
(8x – 12) = (6x + 14)
reduce:
2x = 28
x = 14
Call the output f(x)
Call the input x
f(x) = x - 3