a rectangular prism has a square base with a side length of 10 inches. The volume of the prism is 1,600 cubic inches. Find the s
1 answer:
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The horizontal distance between the two balloons is 53.8 meters.
<u><em>Explanation</em></u>
According to the below diagram, A and B are the positions of two balloons which are 48.2 meter and 61.0 meter above the ground respectively.
Horizontal distance between two balloons is AC, which is meter.
A person in the left balloon observes that the right balloon is 13.38° above the horizontal. That means, ∠BAC = 13.38°
According to the diagram,
Now in right angle triangle ABC.....
So, the horizontal distance between the two balloons is 53.8 meters.
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14) The perimeter of this square is given as 28a²b⁴
The perimeter formula of a square is P = 4 x side
28a²b⁴ = 4s
7a²b⁴ = s
Area formula of a square is:
A = side²
= ( 7a²b⁴)²
= 49a⁴b⁸
15)
Let's deal with it one by one and combine at the end
Numerator = ( r²st³ )( 20r⁻³s⁻¹t⁻⁴ )
The product of power rule applies here
= ( 20r⁻¹t⁻¹ ) → { r²⁺⁽⁻³⁾s¹⁻¹t³⁺⁽⁻⁴⁾ }
Denominator = ( -4r⁻²t )³
The power of a product rule applies here
= ( -64r⁻⁶t³ ) → ((-4)³(r⁻²ˣ³)(t)³)
Combine =
Quotient of powers rule apply here
Lets separate again:
, 
Final =
16)![\sqrt[3]{x^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E4%7D%20)
The power inside the root will be the numerator and root number will be the denominator
17)
× 
The numerator will be the power inside and the denominator will be the root number
![\sqrt[8]{x^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7Bx%5E3%7D%20)
14) The perimeter of this square is given as 28a²b⁴
The perimeter formula of a square is P = 4 x side
28a²b⁴ = 4s
7a²b⁴ = s
Area formula of a square is:
A = side²
= ( 7a²b⁴)²
= 49a⁴b⁸
15)
Let's deal with it one by one and combine at the end
Numerator = ( r²st³ )( 20r⁻³s⁻¹t⁻⁴ )
The product of power rule applies here
= ( 20r⁻¹t⁻¹ ) → { r²⁺⁽⁻³⁾s¹⁻¹t³⁺⁽⁻⁴⁾ }
Denominator = ( -4r⁻²t )³
The power of a product rule applies here
= ( -64r⁻⁶t³ ) → ((-4)³(r⁻²ˣ³)(t)³)
Combine =
Quotient of powers rule apply here
Lets separate again:
Final =
16)
The power inside the root will be the numerator and root number will be the denominator
17)
The numerator will be the power inside and the denominator will be the root number