- x - 3( x - 2 ) = 3 ( 2 - x )
Multiply 3 with x - 2 on LHS and 3 with 2 - x on RHS
Now take -3x to LHS and change its symbol to +. And take 6 to RHS and change it to negative.
-3x and 3x will cancel out and also 6 and -6 will also get cancelled out.
<u>Answer</u><u>:</u>
<u>x </u><u>=</u><u> </u><u>0</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
Step-by-step explanation:
First I want to set up some variables.
S = sum
n = final term
ax = xth term, so a1 is the first term and an is the last one
d = common difference.
There are two formulas to find the sum, if you don't get how they were gotten I'd be happy to explain.
S = (n/2)(a1+an) = (n/2)(2a1+(n-1)d)
So, to find n we use the first one.
S = (n/2)(a1+an)
123 = (n/2)(8+33)
123 = (n/2)41
3 = n/2
6 = n
Now we can find d with the other one
S = (n/2)(2a1+(n-1)d)
123 = (6/2)(2*8+(6-1)d)
123 = 3(16+5d)
41 = 16+5d
25 = 5d
5 = d
so there are six terms and the common difference is 5.
Answer: False, False, True, True
Step-by-step explanation:
Answer:
h
Step-by-step explanation:
Answer:
1/4
Step-by-step explanation:
