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Leya [2.2K]
3 years ago
6

What is the slope of the line?

Mathematics
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

m = slope

(x_1, y_1) = coordinates of first point in the line

(x_2, y_2) = coordinates of second point in the line

In-s [12.5K]3 years ago
5 0

Answer:

1/4

Step-by-step explanation:

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Help please will mark brainliest!!!!!!
Nimfa-mama [501]
<h3>Solution : </h3>

\bf Speed = \dfrac{\dfrac{4}{5}}{\dfrac{1}{6}}

\bf Speed = \dfrac{4}{5} \times \dfrac{6}{1}

\Large \boxed{\bf Speed = \dfrac{24}{5}}

\pink{\bf So, \: the \: answer \: is \: \dfrac{24}{5} \: miles \: per \: hour}

5 0
3 years ago
Read 2 more answers
find a function whose second derivative is y''=12x-2 at each point (x,y) on its graph and y=-x+5 is tangent to the graph at the
pogonyaev
Start by integrating y'' twice to get function y(x).

y' = \int (12x - 2) dx = 6x^2 -2x + c \\  \\ y = \int (6x^2 -2x+c )dx= 2x^3-x^2 +cx+d

Next find value of coefficients 'c' and 'd' using the given tangent line
The slope of tangent line is equal to y' when x=1.

6x^2 -2x+c = -1, x = 1 \\  \\ 6-2+c = -1 \\  \\ c = -5

The tangent line intersects the curve y(x) when x = 1.
If x = 1, then y = 4  (From y =-x+5)

y = 2x^3 -x^2-5x +d , x = 1, y = 4 \\  \\ 2-1-5+d = 4 \\  \\ d = 8

Final Answer:
y = 2x^3 -x^2 -5x+8
3 0
3 years ago
Please help, no links please I really need help.
Lady bird [3.3K]

Answer:

C.

Step-by-step explanation:

7 0
3 years ago
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What is –22x+9x simplified ​
rodikova [14]

Answer:

I think -13 x and thanks for point

5 0
3 years ago
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1. Homer has an idea for a new donut shop. He wants to design the donut shop so that the rectangular
Tju [1.3M]

Solving a <em>system of equations</em>, it is found that since the <u>quadratic equation has two positive roots</u>, they can be the values of the length and the width, and the design is possible.

The perimeter of a <u>rectangle of length l and width w</u> is given by:

P = 2(l + w)

The area is:

A = lw

In this problem, perimeter of 63.5 m, hence:

2l + 2w = 63.5

2l = 63.5 - 2w

l = 31.75 - w

Area of 225 m², hence:

lw = 225

(31.75 - w)(w) = 225

w^2 - 31.75w + 225 = 0

Which is a quadratic equation with coefficients a = 1, b = -31.75, c = 225.

Then:

\Delta = b^2 - 4ac = (-31.75)^2 - 4(1)(225) = 108.0625

w_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{31.75 + \sqrt{108.0625}}{2} = 21.1

w_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{31.75 - \sqrt{108.0625}}{2} = 10.68

Since the <u>quadratic equation has two positive roots</u>, they can be the values of the length and the width, and the design is possible.

A similar problem is given at brainly.com/question/10489198

6 0
2 years ago
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