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snow_lady [41]
3 years ago
11

he net of a solid figure is shown below: Four squares are shown side by side in a row. The second square has a square above it a

nd a square below it. All the squares have side length equal to 4 inches Which calculation will give the total surface area of the solid figure? 6 ⋅ 4 ⋅ 4 square inches 4 ⋅ 6 ⋅ 6 square inches 6 ⋅ 4 ⋅ 4 ⋅ 4 square inches 4 ⋅ 6 ⋅ 6 ⋅ 6 square inches
Mathematics
1 answer:
Travka [436]3 years ago
6 0

Answer:

A. 6 ⋅ 4 ⋅ 4 square inches

Step-by-step explanation:

From the given question, it would be observed that all the squares have the same dimensions.

Thus,

the total number of squares in the net = 6

surface area of a square in the net = 4 x 4

                                            = 16 in^{2}

so that,

total surface area of the solid figure = 16 x 6

                                            = 96 in^{2}

Also,

6 ⋅ 4 ⋅ 4 = 96 in^{2}

Therefore, the total surface area of the solid figure can be expressed as 96 in^{2}. The appropriate option is A.

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Paul has three cube-shaped boxes. Each box is a different size
qwelly [4]

Answer:

See explanation

Step-by-step explanation:

Paul has three cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below.

  • The combined volume of the three boxes is 1,197 cubic inches.
  • The area of one face of the medium box is 49 square inches.
  • The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. The medium box has the area of one face of 49 square inches, then

a^2=49\\ \\a=7\ inches

is the side length.

The volume of the medium box is

a^3=7^3=343\ in^3.

2. The volume of the smallest box is 218 cubic inches less than the volume of the medium box, then the volume of the smallest box is

343-218=125\ in^3.

Ib is the side length, then

b^3=125\\ \\b=5\ inches

The area of one face is

b^2=5^2=25\ in^2.

3. The volume of the largest box is

1,197-343-125=729\ in^3,

then if c is the side length,

c^3=729\\ \\c=9\ inches.

4. The total height of the stack is the sum of all sides lengths:

a+b+c=7+5+9=21\ inches

5. Find the surface area of each box:

  • small 6b^2=6\cdot 5^2=6\cdot 25=150\ in^2;
  • medium 6a^2=6\cdot 7^2=6\cdot 49=294\ in^2;
  • large 6c^2=6\cdot 9^2=6\cdot 81=486\ in^2.

In total, Paul needs

150+294+486=930\ in^2

of wrapping paper. He has 1,000 square inches, so Paul has enough paper to wrap all 3 boxes.

8 0
4 years ago
Simplify. 3{[9(x-2)+7]-2[4(x+5)-36]}
Tcecarenko [31]
The answer would be 69
7 0
4 years ago
What is the value of (-3/4)^-4
blsea [12.9K]

Answer:

256/81

Step-by-step explanation:

According to the formula:

a^{-b}=1/a^{b}

Using the above formula to solve the question, we perform following steps:

(-3/4)^{-4}=1/(-3/4)^{4}

                    =4^{4}/(-3)^{4}

                    =(4*4*4*4)/(-3*-3*-3*-3)

                     =256/81 which is the required answer.

8 0
3 years ago
Read 2 more answers
Angle LMP and angle PMN are complementary. Find the value of x.
Kryger [21]
Complimentary angles add up to 90 degrees

2x + 4x = 90
6x = 90
x = 90/6
x = 15 <==
4 0
3 years ago
Read 2 more answers
mrs.Smith wants to give 2 hotdogs to each of her 27 guest.Hotdogs come in packages 10 of hotdogs will mrs.smith need to buy.​
Mice21 [21]

Answer:

6 packages

Step-by-step explanation:

27 guests x 2 hotdogs = 54 hotdogs

54 hotdogs/packages of 10 = 5.4

round up because 5 packages wouldn't be enough -- so Mrs. Smith needs 6 packages :)

6 0
3 years ago
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