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Darina [25.2K]
2 years ago
12

If one of the roots of the equation x² – 4x + k = 0 exceeds the other by 2, then find the roots and determine the value of k.

Mathematics
2 answers:
vladimir1956 [14]2 years ago
7 0

Answer:

The roots are 1 and 3.

k = 3.

Step- by-step explanation:

We use the facts that if α and β are the roots of ax^2 + bx + c = o then α+ β = -b/a and  α β = c/a.

The roots are written as  α and α+2, then:

α + α + 2 = -(-4)

2α + 2 = 4

α + 1 = 2

α = 1

also

α (α + 2) = k

Substituting for α:

1(1 + 2) = k

k = 3.

The roots are 1 and 1 + 2 = 3.

Verizon [17]2 years ago
3 0

Step-by-step explanation:

the solutions for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -4

c = k

x = (4 ± sqrt(16 - 4k))/2 = 2 ± sqrt(4 - k)

x1 = 2 + sqrt(4 - k)

x2 = 2 - sqrt (4 - k)

x1 = 2 + x2

2 + sqrt(4 - k) = 2 + 2 - sqrt(4 - k)

2×sqrt(4 - k) = 2

sqrt(4 - k) = 1

4 - k = 1

k = 4 - 1 = 3

x1 = 3

x2 = 1

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3 years ago
Find the product of 2x^(4x² + 3x + 1). (1 point)
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Step-by-step explanation:

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2 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Jobisdone [24]

Answer:

f(x)=x^4-9x^2-50x-150

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))

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3 0
3 years ago
13 + 11s = -15 + 8s − 20
koban [17]

<em>Answer,</em>

<em><u>S = -16</u></em>

<em>Explanation,</em>

<em><u>Step 1: Simplify both sides of the equation.</u></em>

<em>13 + 11s = − 15 + 8s − 20</em>

<em>13 + 11s = − 15 + 8s + − 20</em>

<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>

<em>11s + 13 = 8s + − 35</em>

<em>11s + 13 = 8s − 35</em>

<em><u>Step 2: Subtract 8s from both sides.</u></em>

<em>11s + 13 − 8s = 8s − 35 − 8s</em>

<em>3s + 13 = − 35</em>

<em>Step 3: Subtract 13 from both sides.</em>

<em>3s + 13 − 13 = − 35 − 13</em>

<em>3s = − 48</em>

<em><u>Step 4: Divide both sides by 3.</u></em>

<em>3s/3 = −48/3</em>

<em>s = -16</em>


<u><em>Hope this helps :-)</em></u>


3 0
3 years ago
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