Question

Can someone please help me please help me I really need help please help me .

Answer 1

Answer:

$B) sin(\alpha )$

Step-by-step explanation:

$sin(90-0)=Cos(0)$

$Cos(90-0)=sin(0)$

$So...$

$Cos(90-\alpha )= sin(\alpha )$

$------------$

hope it helps...

have a great day!!

Answer 2

Answer:

cos(90°-a)

since it lies in first quadrant

sina

your option is B.sin(a)