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Elena L [17]
2 years ago
6

Can someone please help me please help me I really need help please help me .

Mathematics
2 answers:
Mariulka [41]2 years ago
5 0

Answer:

B) sin(\alpha )

Step-by-step explanation:

sin(90-0)=Cos(0)

Cos(90-0)=sin(0)

So...

Cos(90-\alpha )= sin(\alpha )

------------

hope it helps...

have a great day!!

pochemuha2 years ago
3 0

Answer:

cos(90°-a)

since it lies in first quadrant

sina

your option is B.sin(a)

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The potential energy, P, in a spring is represented using the formula P = kx2. Lupe uses an equivalent equation, which is solved
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So, kx^{2} =P and

k=\frac{P}{x^{2} }

If we compare this equation with the given options, we can easily find that this matches with the last one k=\frac{p}{2x^{2} } with P = p/2.

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3 years ago
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The error is about 3.5%
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Identify which of the following variables are discrete and which are continuous: a. Number of warts on a toad b. Survival time a
gulaghasi [49]

Answer:

1. Number of warts on a toad ⇒ <em>discrete  variable</em>

2. Survival time after poisoning ⇒ <em>continuous  variable</em>

3. Temperature of porridge ⇒ <em>continuous  variable</em>

4. Number of bread crumbs in 10 meters of trail ⇒ <em>discrete  variable</em>

5. Length of wolves’ canines ⇒ <em>continuous variable</em>

A discrete variable is the one which takes over range of real number, for a value in range that variables are permitted to take, there is minimum distance to nearest permissible value. In contrast, continuous variables are the one which can take infinitely many values.  

4 0
2 years ago
WILL GIVE BRAINLIEST Chang deposited $5000 into an account with a 4.8% annual interest rate, compounded monthly. Assuming that n
Mariulka [41]

Answer:

9.42 years (= 113 months)

Step-by-step explanation:

Use the compound rate interest formula:

A=P(1+\frac{r}{n})^{nt}

where:

  • A = amount
  • P = principal
  • r = interest rate (in decimal format)
  • n = number of times interest is compounded per unit t
  • t = time

Given:

  • A = $7850
  • P = $5000
  • r = 4.8% = 0.048
  • n = 12
  • t = years

\implies 7850=5000(1+\frac{0.048}{12})^{12t}

\implies 7850=5000(1.004)^{12t}

\implies \dfrac{7850}{5000}=(1.004)^{12t}

\implies 1.57=(1.004)^{12t}

Take natural logs:

\implies \ln1.57=\ln(1.004)^{12t}

\implies \ln1.57=12t\ln(1.004)

\implies t=\dfrac{\ln 1.57}{12 \ln1.004}

\implies t=9.42\textsf{ years (nearest hundredth)}

\implies t=113 \textsf{ months}

5 0
1 year ago
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