The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
The plane went 100 meters higher than its original height
Answer:
D
Step-by-step explanation:
If you figure out the median you'll see that for 8th grafe its 21 and 7th 25 therefore 4 points higher
Answer:
3.50
Step-by-step explanation:
1.50 x 2 = 3 And their is .50 left so half of 1 pound is .50 which is 3+50=3.50
If this helped please make me brainliest :)
Answer:
2187.5 cubic meters of water
Step-by-step explanation:
Volume of rectangle = L * W * D
V = 50 * 25 * 1.75
V = 2187.5
