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Rasek [7]
3 years ago
10

What is the area of an octagon when the 8 sides are 5​

Mathematics
1 answer:
katrin [286]3 years ago
6 0

Answer:

40cm² there you go

Step-by-step explanation:

Area =side×side so 8×5=40

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Omar says that the least common multiple of 9 and 6 is 54. Which is true about Omar's statement?
Damm [24]

Hey there!

Let's pull out the multiples of each number and see which ones fall in line first.

9,18

6,12,18

The LCM is 18. Therefore, answer B and D are incorrect. A is incorrect because 9 * 6 is 54. Therefore, the answer is C.

I hope this helps!

5 0
3 years ago
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What is the unit rate for 16 ounces (pint) at $3.93?
Juli2301 [7.4K]

Answer:

25 cents/ounce

Step-by-step explanation:

The unit rate means how much is one of the thing you are working with.  In this case, the unit rate of a pint (16 ounces) is how much just one ounce will cost.  So divide $3.93 by 16

$3.93/16 =  $0.245625

Since we're working with money, round to the nearest hundredth

Unit rate is $0.25 per ounce, or 25 cents per ounce

8 0
3 years ago
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What two numbers multiply to and add to -32 add to -4
Ket [755]

Answer:

-36

Step-by-step explanation:

7 0
2 years ago
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Please help
ioda

Answer:

im 12!! how do you do this

Step-by-step explanation:

3 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
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