<h3>
Answer: 1/12</h3>
Explanation:
Draw a rectangle. Then draw three vertical lines inside to split the rectangle into 4 equal pieces. Shade one of the pieces to represent 1/4.
Now draw 2 horizontal lines to split that 1/4 piece into three equal smaller pieces. You should end up with a 3 by 4 grid of small squares. There are 3*4 = 12 small squares total.
Each person gets 1/12 of a unit of ribbon, when we started off with 1/4 of a unit of ribbon. Notice how 3*(1/12) = 3/12 = 1/4.
Refer to the diagram below.
If the width of the reactangle is x=13, the area of the rectangle is:
A(13)=2*(13)^2-5*(13)
A(13)=2*(169)-65
A(13)=338-65
A(13)=273
The area of the rectangle is 273 square units
For the information given, a line segment of 4 inches can be drawn
<h3>How to illustrate the segment?</h3>
For the 'copy', you would measure the line drawn, and duplicate it to the right, measuring it to make sure it is the exact length of the first line.
To bisect the original line segment, measure the line with a ruler or other device, and calculate 1/2 distance from one end, mark it, measure from left end to mark, make sure right section is equal in length.
Draw an angle of 90 degree and label it to avoid confusion. Now use a scale to draw a ray and label the vertex point so we can know the point where to place compass. Use compass to draw an arc on angle. This angle will help you measure where to put the new point on our new angle.
Similarly draw the same arc on the new ray. This is the first step in finding the new point. Then, use compass to measure the difference between the two places where the arc meets the angle on angle.
Furthermore, use the measurements from the previous step to draw another arc. This step is to help establish a point where the two arcs meet. Now draw a point where the two arcs met and drew a line through it.
Learn more about segment on:
brainly.com/question/2437195
#SPJ1
(6) 70, 70, 110
∠2 = ∠4 = 110° ( congruent angles )
∠3 = 180° - 110° = 70° ( straight angle )
∠1 = 70° ( vertically opposite ∠3 )
(9) ∠AEC = 15x - 11
since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1
∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11
(7) x = 3
AC = AB + ABC = 32
2x + 6x + 8 = 32
8x + 8 = 32 ( subtract 8 from both sides )
8x = 24 ( divide both sides by 8 )
x = 3
