Answer:
The measure of the angle JKG is:
m∠JKG = 56°
Step-by-step explanation:
<u>Given</u>
m∠JKG = 76-2x
m∠FHK = 6x-4
J is a midpoint of the segment FG and K is a midpoint of the segment GH.
<u>To determine</u>
m∠JKG = ?
Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH
We know that two triangles are similar if the only difference is size. So, the angles remain the same.
so m∠JKG and m∠FHK are equal.
i.e.
m∠JKG = m∠FHK
substitute m∠JKG = 76-2x and m∠FHK = 6x-4
76-2x = 6x-4
6x+2x = 76 + 4
8x = 80
divide both sides by 8
8x/8 = 80/8
x = 10
Therefore, the value of x = 10
As
m∠JKG = 76-2x
substitute x = 10
m∠JKG = 76 - 2(10)
= 76 - 20
= 56°
Therefore, measure of the angle JKG is:
m∠JKG = 56°
68.40 divide 6 = 11.4
41.80 divided 4= 10.45
Plan B is lower fee per lesson
Answer:
surface area is 39
Step-by-step explanation:
add the areas of each geometric figure making up the composite 3D figure.
first 3D figure
2+2+6+6
=16---eq 1
from third 3D figure
4+4+10+5
= 23
from 1 and 2
16+23
= 39
may be!! I'm not sure bout this answer
I'm not exactly sure of what you mean, but if the number (for example) were 2,3, and 6 you could say 2 and 6 multiply to get 6 and 6 divided by 2 would be 3 and so on. You could do this with any operation. Hope this helps, and sorry if this wasa little unclear.
Answer:
30.11 meters ( approx )
Step-by-step explanation:
Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )
Given,
Point A is 8.20 m above level ground,
So, the height of the building = ( x + 8.20 ) meters,
Now, 1 degree = 60 minutes,
⇒ 
By the below diagram,
Now, again by the below diagram,
Hence, the height of the building = x + 8.20 = 30.11 meters (approx)
