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melisa1 [442]
3 years ago
7

Find the distance between (-2,4) & (5, 1) on the CCS. Please explain how you did it please.

Mathematics
1 answer:
krok68 [10]3 years ago
3 0
A(x1, y1), B (x2,y2)

d=V(y2-y1)^2+(x2-x1)^2

d^2= (1-4)^2+[5-(-2)]^2=(-3)^2+ (5+2)^2=9+49=58

d=V58
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