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3 years ago

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Mathematics

1 answer:

Dvinal [7]3 years ago

5 0

The volume of the figure is 54 cubic units

<h3>Area of a rectangular prism.</h3>

Since we are not given a figure, we can assume it as a rectangular prism:

Area of the rectangular prism = a²b

a² is the base area
b is the height of the prism

Given that a = 3 units and b = 6 units, the required volume is expressed as:

V = 3² * 6

V = 9 * 6

V = 54 cubic units

Hence the volume of the figure is 54 cubic units

Learn more on volume of prism here: brainly.com/question/23963432

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Please solve this question <br> (2x3)x2+5x2

oksano4ka [1.4K]

(2×3)×2+5×2=22

2×3=6

6×2+5×2

12+5×2

12+10

22

5 0

3 years ago

The perimeter of the rectangle below is 112 units. Find the length of side VW . Write your answer without variables. Top YX: 4z

dimaraw [331]

Answer:

$VW = 33$

Step-by-step explanation:

<em>See attachment for complete question</em>

Given

$VY = 4x - 1$

$VW = 5x + 3$

$Perimeter = 112$

Required

Determine the length of VW

Perimeter is calculated as:

$Perimeter = 2 * (Width + Length)$

This gives:

$Perimeter = 2 * (VW + VY)$

Substitute values for VW, VY and Perimeter

$112 = 2 * (4x - 1 + 5x + 3)$

Collect Like Terms

$112 = 2 * (4x + 5x -1 +3)$

$112 = 2 * (9x +2)$

Divide through by 2

$56 = 9x + 2$

Collect Like Terms

$9x = 56 - 2$

$9x = 54$

$x = 54/9$

$x = 6$

Substitute 6 for x in $VW = 5x + 3$

$VW = 5 * 6 + 3$

$VW = 30 + 3$

$VW = 33$

4 0

3 years ago

Evaluate the following algebraic expression

anastassius [24]

Answer:

Step-by-step explanation:

13-5=8

8*8=64

7 0

3 years ago

Read 2 more answers

The body of a 154 pound person contains approximately 4 × 10-1 milligrams of gold and 16 × 101 milligrams of aluminum. Based on

Eddi Din [679]

The number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

<u><em>Explanation</em></u>

Lets assume, the number of milligrams of aluminum is $x$ times the number of milligrams of gold in the body.

The body of a 154 pound person contains approximately 4 × 10⁻¹ milligrams of gold and 16 × 10¹ milligrams of aluminum.

So the equation will be...

$(4*10^-^1)*x= 16*10^1\\ \\ x= \frac{16*10^1}{4*10^-^1}= 4*10^2=400$

So, the number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

3 0

4 years ago

Pls help I will give you 15 points

STALIN [3.7K]

Answer:

Ana still needs to read 1/5 of th journal

8 0

3 years ago