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RUDIKE [14]
3 years ago
14

_____% of 145 = 75 48.3% 193.3% 76.5% 51.7%

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0
48.3 i’m pretty sure! your welcome:)
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\frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = \frac{12}{60}=\frac{1}{5}

Probability of getting 2 = \frac{17}{60}

Probability of getting 3 = \frac{15}{60}=\frac{1}{4}

Probability of getting 4 = \frac{16}{60}=\frac{4}{15}

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: \frac{17}{60}

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: \frac{1}{4}

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: \frac{7}{15}

This is not obtained above. So, it is not the experimental probability.

Option E: \frac{12}{43}

This is not obtained above. So, it is not the experimental probability.

Hence \frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

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Step-by-step explanation:

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