Question

Write a program, which will display the menu with 5 items. It will ask the use to give their choice. It will trap all possible errors and then print the result when correct input is provided before exiting the program.

Answer 1

Answer:

The program in Python is as follows:

print("Welcome to sorting program")

print("1. Title")

print("2. Rank")

print("3. Date")

print("4. Start")

print("5. Likes")

while(True):

   choice = input("Enter a choice between 1 and 5 only: ")

   if choice.isdigit() == True:

       if(int(choice)>=1 and int(choice)<=5):

           print("You entered valid choice", choice)

           break;

       else:

           print("You have not entered a number between 1 and 5. Try again")

   else:

       print("You entered an invalid choice")

Explanation:

This prints the header

print("Welcome to sorting program")

The next 5 lines print the instructions

print("1. Title")

print("2. Rank")

print("3. Date")

print("4. Start")

print("5. Likes")

The loop is repeated until it is forcefully exited

while(True):

This prompts the user to enter a choice

   choice = input("Enter a choice between 1 and 5 only: ")

This checks if the choice is a digit

   if choice.isdigit() == True:

If yes, this checks if the choice is between 1 and 5 (inclusive)

       if(int(choice)>=1 and int(choice)<=5):

If yes, this prints valid choice and the choice entered

           print("You entered valid choice", choice)

The loop is exited

           break;

If the choice is out of range

       else:

This prints the error and tells the user to try again

           print("You have not entered a number between 1 and 5. Try again")

If choice is not a digit

   else:

This prints invalid choice

       print("You entered an invalid choice")