Which is the graph of the equation y-1 =

Mathematics

1 answer:

Alex73 [517]3 years ago

7 0

Answer: 60

Just put 60 :)

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A supermarket reduced the price per pound whole chicken by 20%. How many pounds of chicken can now be purchased for the amount o

nignag [31]

Answer:

25 pounds

Step-by-step explanation:

Let us assume that initially, 1 pound of whole chicken costs x.

So, initially 20 pounds of whole chicken costs 20x.

Now, the price is reduced by 20%.

That means that 1 pound of whole chicken now costs $x[1-\frac{20}{100} ]=0.8x$

Therefore, with a 0.8x amount of money, we can now purchase 1 pound of the whole chicken.

Hence, with a 20x amount of money, we can now purchase $\frac{20x}{0.8x}=25$ pounds of the whole chicken.

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4 years ago

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3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :