To solve this you would use the pythagorean theorem since the brace is making the frame look like two right triangles. The theorem states that for a triangle with a right angle, A^2+B^2=C^2. A and B are the sides of the frame and C is the brace which is like the hypotenuse of the triangle. It doesn't matter which side is A or B so you can put 6 or 8 in place of either in the equation. 6^2+8^2=C^2. If you simplify this it equals 36+64=C^2, which then simplifies to 100=C^2. Then you take the square root of both sides (what number multiplied by itself = the number you are trying to get, in this case, 100). So then you get C=10 because 10x10=100. So the length of the diagonal brace is 10ft.

4 0

2 years ago

Discussion Prompt: A fair coin is tossed twice and the number of heads is recorded. Jose says the P(1 head) = 1/2, while Jeff st

NemiM [27]

Let H represent heads and T represent tails.

Writing HH means we get two heads and HT means we get heads first, then tails second, and so on.

We have these four possible outcomes when flipping two coins

Of those four outcomes, two of them have exactly one head show up (HT and TH). The probability of getting exactly one head is 2/4 = 1/2, so this is why Jose is correct.

8 0

2 years ago