First, you need to get the denominators (the bottom number) the same. The smallest number to get them to is 15.
So, what you need to do is take 2/5 and multiply the bottom by 3 to get 15, and since you did it to the bottom, you need to do it to the top too. So you would get, 6/15.
Then, for 1/3, take the bottom number and multiply it by 5. Then, since you did it to the bottom, do it to the top as well. You would get 5/15.
Then, you need to put them side by side. You don't add the bottom, so your denominator would remain 15, but your numerator (top) would get added.
<u> 6</u> + <u>5</u> = <u>11</u>
15 15 15
Given:
In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.
To find:
The measure of angle P.
Solution:
According to the Law of Cosines:

Using Law of Cosines in triangle OPQ, we get




On further simplification, we get




Therefore, the measure of angle P is 79 degrees.
Answer:
60 km/h
Step-by-step explanation:
Let us use the x to represent the speed of the car since it is the smaller value.
Then, the distance covered by the car is 4x since was going 4 kph.
The distance covered by the train is (x+5) times 7 or 7x+35.
We know that the total distance covered is 640 km.
Using this information, we can set up the equation 4x+7x+35=640.
By subtracting both sides by 35 and combining the x's, we get a new equation of 11x=605.
After this, we divide both sides by 11 and get x=55.
Lastly, we add 5 to 55 since the train is 5 km faster than the car and that x stood for the car.
Train=60 km/h
The expression of integral as a limit of Riemann sums of given integral
is 4
∑
from i=1 to i=n.
Given an integral
.
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=
∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=![[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}](https://tex.z-dn.net/?f=%5Bn%5E%7B2%7D%28n%2B4i%29%5D%2F2n%5E%7B3%7D%2B%28n%2B4i%29%5E%7B3%7D)
∑f(a+iΔx)Δx=
∑
=4
∑
Hence the expression of integral as a limit of Riemann sums of given integral
is 4
∑
from i=1 to i=n.
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