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2 years ago

RIGHT triangular prisms A and B are congruent. What is the volume of prism B? A) 420 in3 B) 1080 in3 C) 2160 in3 D) 32400 in3

Mathematics

1 answer:

Nookie1986 [14]2 years ago

7 0

Answer: B

Step-by-step explanation:

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What is the expression of three more than twice a number k

sesenic [268]

Answer:

3 + 2k

Step-by-step explanation:

<u>Step 1: Convert words into an expression</u>

Three more than twice a number k

3 + 2k

Answer: 3 + 2k

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4 years ago

Xavier earns $11.50 per hour working at the nearby grocery store. Last week, Xavier worked for 13.5 hours. How much money did Xa

olga55 [171]

Answer: Xavier earned $155.25 last week.

Step-by-step explanation:

To find out how much Xavier earn last week, we need to multiply how much He earns per hour ($11.50) by how many hours He worked last week (13.5h), so:

11.50 * 13.5 = 155.25

155.25 is already round to the nearest penny.

So, Xavier earned $155.25 last week.

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3 years ago

Find the value of x 29 (6x + 1)

nignag [31]

The answer would be x (x+1)

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3 years ago

Read 2 more answers

The equation of a circle is x2 + y2 + Cx + Dy + E = 0. If the radius of the circle is decreased without changing the coordinates

tatyana61 [14]

Answer:

There will be no change in C and D but E must increase.

Step-by-step explanation:

We are given a equation of circle as:

$x^2+y^2+Cx+Dy+E = 0$

it could also be represented in general form of equation of circle as:

$(x+\dfrac{C}{2})^2+(y+\dfrac{D}{2})^2=\dfrac{C^2}{4}+\dfrac{D^2}{4}-E$

( since we add both the side of the equality by $\dfrac{C^2}{4}$ and $\dfrac{D^2}{4}$ )

Hence, on comparing the equation with general form of the equation:

$(x-g)^2+(y-h)^2=r^2$

The center of circle is (g,h) and radius is r.

Here we have the center as:

$(\dfrac{-C}{2},\dfrac{-D}{2})$

and radius is given aS:

$r=\sqrt{\dfrac{C^2}{4}+\dfrac{D^2}{4}-E}\\\\r=\sqrt{\dfrac{C^2+D^2-4E}{4}$

$r=\dfrac{\sqrt{C^2+D^2-4E}}{2}$

As there is no change in the center hence the value of $\dfrac{-C}{2}$ and $\dfrac{-D}{2}$ remains unchanged i.e. the value of C and D remains unchanged.