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3 years ago

Help with this pleeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeease lol

Mathematics

2 answers:

storchak [24]3 years ago

8 0

Answer:

6- D

4- A

3- A

Step-by-step explanation:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

6. = D

4. = A

Step-by-step explanation:

6. 2(2.5)= 5

4(2.5)= 10

6(2.5) =15

9(2.5) is not 21 its 22.5

4. 125÷5 = 25

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Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago

Find the equation of this line<br><br> y = [?]x + [ ] <br> Please help

larisa [96]

<h2>Writing an Equation of a Line in Slope-Intercept Form</h2><h3>Answer:</h3>

$y = [ -2 ] x + [ 1 ]\\$

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about Slope-Intercept Form: <u>brainly.com/question/24599351</u></em>

We must first find the slope.

<em>Please refer to my Answer from this Questions to know more about Slopes of a Line:</em>

<em><u>brainly.com/question/24640665</u></em>
<em><u>brainly.com/question/24638053</u></em>

We can see the marked points, $(0,1)$ and $(4, -7)$ , are on the line.

Solving for the slope:

$m = \frac{y_2 -y_1}{x_2 -x_1} \\ m = \frac{-7 -1}{4 -0} \\ m = \frac{-8}{4} \\ m = -2$

Now we can now solve for the $y$ -intercept.

<em>Please refer to the second paragraph of my Answer from this Question to know more about y-intercepts: <u>brainly.com/question/24606058</u></em>

We can see that the line intersected the $y$ -axis at $(0,1)$ so $b = 1$ .

5 0

3 years ago

Pls help me !!!!!!!!!!!!!!!!!!!!!!!!

Vikentia [17]

Answer:

9.89 m

Step-by-step explanation:

AC is the hypotenuse (H)

x is the opposite (O)

O and H are in sine

sin=O/H

H=O/sin

H=7.9/sin(53)

=9.89187169943418

3 SF

9.89 m

8 0

3 years ago

Read 2 more answers

Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18

faust18 [17]

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29

b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59

c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88

d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12

e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24

f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59

3 0

3 years ago

Read 2 more answers