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dolphi86 [110]
3 years ago
9

If they must form an ethics subcommittee of 4 members,l how many different subcommittees are possible

Mathematics
1 answer:
Mila [183]3 years ago
3 0
I need this answer too can someone please help us out with the right answer ?!

Explanation: ?
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A coastline recedes at a rate of 3cm per year. How much of the coastline dissappears after 4 years?
Damm [24]

Answer:

12 cm of coastline

Step-by-step explanation:

Multiply the years (factor) by the receding amount, 3cm, (constant) BAM answer.

3 0
3 years ago
PLEASE HELP! I WOULD APPRECIATE IT SO MUCH. IF ANSWERED, PLEASE USE THE PYTHAGOREAN THEOREM!
Nata [24]

To find out how far Rachel walked round trip, we first need to find out how long the fastest way between her house and the park is. In the picture, we see a common Pythagorean Triple (the possibility for the sides of a right triangle). The triple with 3 and 4 is 3, 4, and 5. That means that the last side is 5. That means that the total distance is 3 + 4 + 5 km or 12 km. But, if you would like to solve this using the Pythagorean Theorem, one can do it as follows. Since the legs of the triangle are 3 and 4, the hypotenuse squared would be 3² + 4² = 9 + 16 = 25. To find the hypotenuse, we have to find the square root of 25 which is 5, which leads us to the same answer as before.

8 0
3 years ago
In the rectangular pyramid below, l=30, w=20, and h=28. What is the length of s?
Musya8 [376]

Answer:

A=lw+l(w

2)2+h2+w(l

2)2+h2=30·20+30·(20

2)2+282+20·(30

2)2+282≈2127.25933

Your answer is 2127.259

I think it will help you

5 0
3 years ago
100 points.. please help?
puteri [66]

The fromula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points J(-5, 6), K(3, 4) and L(-2, 1). Substitute:

|JK|=\sqrt{(3-(-5))^2+(4-6)^2}=\sqrt{8^2+(-2)^2}=\sqrt{64+4}=\sqrt{68}\\\\=\sqrt{4\cdot17}=\sqrt4\cdot\sqrt{17}=2\sqrt{17}\\\\|JL|=\sqrt{(-2-(-5))^2+(1-6)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+25}=\sqrt{34}\\\\|KL|=\sqrt{(-2-3)^2+(1-4)^2}=\sqrt{(-5)^2+(-3)^2}=\sqrt{25+9}=\sqrt{34}

The perimeter of ΔJKL:

P_{\Delta JKL}=|JK|+|JL|+|KL|\\\\P_{\Delta JKL}=2\sqrt{17}+\sqrt{34}+\sqrt{34}=2\sqrt{17}+2\sqrt{34}=2(\sqrt{17}+\sqrt{34})

The area of ΔJKL:

A_{\Delta JKL}=\dfrac{1}{2}|JL||KL|\\\\A_{\Delta JKL}=\dfrac{1}{2}\cdot\sqrt{34}\cdot\sqrt{34}=\dfrac{1}{2}(\sqrt{34})^2=\dfrac{1}{2}(34)=17

4 0
3 years ago
Solve the inequality, -3/2<3x
MArishka [77]

For this case we must resolve the following inequality:

- \frac {3} {2}

So, if we divide by 3 on both sides of the equation we have:

\frac {- \frac {3} {2}} {3}

Thus, the solution is given by all the values of "x" greater than - \frac {1} {2}

Answer:

The solution to inequality is:

(- \frac {1} {2};∞)

5 0
3 years ago
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