It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
ttd2
Step-by-step explanation:
You haven't provided the steps.
mathisfun.com/geometry/construct-linebisect.html
Here is a useful link to the correct steps. The instructions may not be exactly the same but I think you can do it.
Answer:
The coordinates of other point are: (5,1)
Step-by-step explanation:
Given coordinates are:
M(x,y) = (2,4)
R(x_1,x_2) = (-1,7)
We have to find the coordinates of other point (x2,y2)
The formula for mid-point is given by:
Putting the values we get
Putting respective elements equal
Hence,
The coordinates of other point are: (5,1)
Answer:
a
Step-by-step explanation:
