Hey there
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The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
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Hope this helps you
Answer: Its the first and third one.
Step-by-step explanation: Lol nope
Answer:
bouton
Step-by-step explanation:
Answer:
y = -4x^2 - 3x + 4
x = 5
y = -4(5)^2 - 3(5) + 4
y = -4(25) - 15 + 4
y = -100 - 15 + 4
y = -114
Step-by-step explanation:
What is the objective? tell me and i can help :)
