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2 years ago

15

Admission to a museum is $7.10 per

1 answer:

yawa3891 [41]2 years ago

7 0

7.1(6)+4.8(6)= 71.4 the answer is $71.4

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if I have a 68% overall and I get a A+ on a final exam that is worth 20% of my grade what would my grade be? There is 86 questio

erik [133]

Answer:

i guess your new grade would be 88%. If you past 100%, you might pass for that grade. Even if you get a 90%, you'll still be able to pass.

Step-by-step explanation:

3 0

2 years ago

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Lemur [1.5K]

Since a and 5 aren't like terms, you would write the expression as $\frac{a+5}{b}$

8 0

3 years ago

Read 2 more answers

Identify a pattern by making a table of the inputs and outputs.

-BARSIC- [3]

it wants you to make a table of the inputs and out puts, and what is the pattern that is happening. like is it a constant increase/decrease and things like that. i'll help you on the table...

x | y

1 | 5

2 | 4

3 | 3

4 | 2

(i am not sure what that 40 is at the end, but You get the point)

now all you have to do is identify the sequence or pattern you see here

3 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

I dont know how to find x

AfilCa [17]

Answer:

not enough info, make another question with the problem attached

Step-by-step explanation:

7 0

2 years ago