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GarryVolchara [31]
3 years ago
8

Using the digits 1, 3, 5, 7 at most once, you can make many three-digit numbers. What is the maximum possible sum of two such di

stinct numbers?
Mathematics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

1504

Step-by-step explanation:

Given the digits :

1, 3, 5, 7

The maximum possible sum of two distinct three digit numbers formed from the digits above will be the sum of the the two hight possible three digit numbers that can be formed.

Highest three digit number = 753

Next highest = 751

The sum of these two. Values gives :

753 + 751 = 1504

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(8,1);((-2,-6)

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60
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7 0
2 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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Answer:

B

Step-by-step explanation:

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