Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
Answer:
1,2,4,29,58,116
Step-by-step explanation:
Prime factorization 116=2x2x29
A increase in price increases the quantity of a item .
<u><em>Answer:</em></u>
a. He will have to read half an article per night
b. Fraction of the reading assignment read each night = 
<u><em>Explanation:</em></u>
<u>Part a:</u>
<u>We are given that:</u>
number of articles to read = 4 articles
number of nights = 8 nights
To get the number of articles that he should read per night, we will simply divide the the number of articles by the number of nights
<u>Therefore:</u>
number of articles to read per night = 
articles per night
<u>Part b:</u>
Now, we know that he will read half an article each night from a total of 4 articles
To get the fraction of the reading assignment read each night, we will divide the number of articles read each night by the total number of assignments
<u>Therefore:</u>
Fraction of the reading assignment read each night =
Hope this helps :)
So if you start with $187.56, and add 49.73, you get?
