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VashaNatasha [74]
3 years ago
5

Please help I don't have much time left

Mathematics
2 answers:
zzz [600]3 years ago
4 0

Answer:

c

Step-by-step explanation:

(2/3)×5

(2/3)×(5/1)

multiply numerator by numerator, denominator by denominator, and you get

10/3 or 3 and 1/3.

german3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Fast help on this!!
Leya [2.2K]

Answer:

5 seconds

Step-by-step explanation:

hope it helps

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3 0
2 years ago
Solve system by elimination <br> 8x-8y=-16<br> -8x-7y=-29
Gnesinka [82]
Add these together.
You get -15y=-45
So y=3

Now plug in to first equation.
8x-8(3)=-16
8x-24=-16
8x=8 so x=1

Check both values in second equation.
-8(1)-7(3)=
-8-21=-29

It works...so x=1, y=3
6 0
3 years ago
15 billion in numerals?
Leokris [45]
A billion has 9 zeros. So
15,000,000,000
:)
4 0
3 years ago
Read 2 more answers
Help with 16 and 17 please
Keith_Richards [23]

Answer:

16) b and 17) C

Step-by-step explanation:

8 0
3 years ago
The final scores from the last five games of two basketball teams are given. Jumping Jackrabbits: 70, 65, 72, 80, 73 Leaping Liz
scoundrel [369]

Using the Mean Absolute Deviation(MAD) concept, it is found that:

a) The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

b) The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation(MAD) of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

Item a:

For the Jumping Jackrabbits, the mean and MAD are given by:

M = (70 + 65 + 72 + 80 + 73)/5 = 72

MAD = (|70 - 72| + |65 - 72| + |72 - 72| + |80 - 72| + |73 - 72|)/5 = 3.6.

For the Leaping Lizards, the mean and the MAD are given by:

M = (61 + 47 + 70 + 63 + 54)/5 = 59

MAD = (|61 - 59| + |47 - 59| + |70 - 59| + |63 - 59| + |54 - 59|)/5 = 6.8.

The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

Item b:

The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

More can be learned about the Mean Absolute Deviation(MAD) concept at  brainly.com/question/3250070

#SPJ1

4 0
2 years ago
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