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3 years ago

Find the average gas bill expense from the months: Oct $48, Nov. $57, Dec $61

Mathematics

2 answers:

Shkiper50 [21]3 years ago

8 0

Answer: $55.33

Remember: To find the average add all the number then, divide by the amount of numbers.

kakasveta [241]3 years ago

3 0

Answer: $55.33

Step-by-step explanation: In order to solve this promblem, add all the monthly gas bills and take that result and divide it by the numbe rof months, to get the anerage gas bill expense

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1. In the figure, m DE = 106 degrees and m BC = 62 degrees. The diagram is not to scale.

k0ka [10]

For question 1, the formula for that is m1= 1/2(a-b). 106 being A and 62 being B. You should get m1=.5*(106-62) which equals B.22

8 0

3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

Read 2 more answers

PLEASE I REALLY NEED HELP!

vagabundo [1.1K]

Answer:

$\frac{3}{28}$

Step-by-step explanation:

Probability (P) is calculated as

P = $\frac{requiredoutcome}{count}$

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = $\frac{3}{8}$

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = $\frac{2}{7}$

P( red and red ) = $\frac{3}{8}$ × $\frac{2}{7}$ = $\frac{6}{56}$ = $\frac{3}{28}$

6 0

3 years ago

SOMEONE HELP PLS 15 POINTS FOR ONE EASY MC QUESTION

Ksenya-84 [330]

Answer:

A rectangle could not be a cross section of a cylinder

could you help me with this: brainly.com/question/21423860

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2 years ago

Difference of squares. Pls help algebra factoring polynomials 10 points

jarptica [38.1K]

Answer:

4x(squared)-36

Step-by-step explanation:

=(2x+−6)(2x+6)

=(2x)(2x)+(2x)(6)+(−6)(2x)+(−6)(6)

=4x^2+12x−12x−36

=4x^2 −36

6 0

2 years ago