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3 years ago

Help please!! Ill give brainliest!!

Mathematics

2 answers:

HACTEHA [7]3 years ago

3 0

Answer:

option C

Step-by-step explanation:

How to find coordinates is over first, then up. the coordinates for Z is left 2, up 0. hope this helps :)

coldgirl [10]3 years ago

3 0

Answer:

z=(-2,0) Choice A

Step-by-step explanation:

to get to point z , we go 2 units to the left (-2)

and up or down 0 units (0)

left or right comes first, then up and down

(-2,0)

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I WILL BE MARKING YOU BRAINLIST! You have to read the statement and see if it is true or false for the blue circle.

larisa86 [58]

Answer:

im pretty sure its false

Step-by-step explanation:

6 0

3 years ago

Petrov ran 7 laps around a track.Each lap around the track is a distance of 1/4 mile. What is the total distance Petrov ran in f

Alla [95]

Answer:

9240 feet

Step-by-step explanation:

Petrov ran 7 laps around a track.Each lap around the track is a distance of 1/4 mile.

Step 1

The total distance Petrov ran in miles is calculated as:

1 lap = 1/4 mile

7 laps = x mile

Cross Multiply

x = 7 × 1/4 mile

x = 1.75 miles

Step 2

What is the total distance Petrov ran in feet?

1 mile = 5280 feet

1.75 miles = x

Cross Multiply

x = 1.75 × 5280 feet

x = 9240 feet

Therefore, the total distance Petrov ran in feet is 9240 feet

3 0

4 years ago

What is 1/10 of 200

tresset_1 [31]

Answer:

Step-by-step explanation:

1/10 is like 200 divided by 10 which is 20

3 0

3 years ago

Which graph represents the function of f(x) = 9x^2 – 36/3x+6?

lubasha [3.4K]

Answer:

This graph represents the function above.

4 0

3 years ago

The mean weight of the seven linebackers was 236 pounds. The first six linebackers weighed 215lb, 305lb, 265lb, 196lb, 221lb, an

Nadya [2.5K]

Answer:

The weight of the seventh linebacker is = 214 lb.

Step-by-step explanation:

Given:

Mean of 7 linebackers = 236 lb

The weights of first 6 linebackers are:

215 lb, 305 lb, 265 lb, 196 lb, 221 lb and 236 lb

To find the weight of seventh linebacker.

Solution:

Let the weight of the seventh linebacker be = $x$

The mean of 7 line backers will be given as:

⇒ $\frac{215+305+265+196+221+236+x}{7}$

The mean of the 7 linebackers is given = 236 lb

Thus, the equation to find $x$ will be :

$\frac{215+305+265+196+221+236+x}{7}=236$

Simplifying.

$\frac{1438+x}{7}=236$

Multiplying both sides by 7.

$7.\frac{1438+x}{7}=236(7)$

$1438+x=1652$

Subtracting both sides by 1438.

$1438-1438+x=1652-1438$

∴ $x=214$

Thus, the weight of the seventh linebacker is = 214 lb.

7 0

3 years ago