Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Since 2.5% as a decimal is .025, the equation to get this is:
(.025)(80000)
Once multiplied, these equal 2,000. Or in other words, the Smiths pay $2,000 in school taxes per year.
The answer is fifty four hundredths
Hi there
The formula is
A=p (1+r)^t
A future value?
P present value 1000
R interest rate 0.07
T time 5 years
So
A=1,000×(1+0.07)^(5)
A=1,402.55
It's a
Hope it helps
