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GaryK [48]
3 years ago
5

Find the equation of the line I in the following picture. The shapes under the lines are squares

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
If you look carefully at the graph, you may see that the slope of the line is
          3-4           -1
---------------- = ------ = m
         7-4             3

thus, you have the slope of the line and two points on the line.  Suppose we
choose the point (4,4) and subst. the known slope and the coordinates of this point into the point-slope formula for the eqn of a str line:

y-y1 = m (x-x1)

y-4 = (-1/3)(x-4)

This is the desired equation.  You could, if you wished, change this into slope-intercept form.
You might be interested in
Find the surface area.
denpristay [2]

Step-by-step explanation:

a rectangular prism (like this brick) has the same basic structure as a cube (like a die) : it has 6 sides.

while a die has 6 equal sides, a rectangular prism has 3 pairs of equal sides :

top and bottom

left and right

front and back

all we have to do is calculate the areas of the 6 rectangles and add them up. that's it.

your remember, the area of a rectangle is

length × width

in our case we have

top and bottom : 2.5×11.5 × 2 = 28.75×2 = 57.5 in²

left and right : 2.5×5 × 2 = 12.5×2 = 25 in²

front and back : 11.5×5 × 2 = 57.5×2 = 115 in²

so, the total surface area of the whole block is

57.5 + 25 + 115 = 197.5 in²

5 0
2 years ago
Explain how you got your answer please :
liraira [26]
X is the number of hours studied, so replace x with 3 in the equation:

y = 6.8(3) + 60
y = 20.4 + 60
y = 80.4

Round down to 80.

The answer would be A.
3 0
3 years ago
in one hour thirty two cars pass through a particular intersection at the same rate how long would it take for 96 cars to pass t
USPshnik [31]

Answer:

72 hours

Step-by-step explanation:

1hour30minutes times 48 cars (since TWO pass every 1:30, not one)

equals 72 hours, or three days

3 0
3 years ago
The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea
Sergeeva-Olga [200]

Answer:

(C)6t^2+5

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5

The correct option is C.

6 0
3 years ago
So I'm currently doing online school due to external circumstances and haven't done this type of problem before. I need help fin
Ann [662]

Answer:

  DE ≈ 14.91

Step-by-step explanation:

Make use of the relationships between sides and angles in a right triangle. These are summarized by the mnemonic SOH CAH TOA:

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

  Tan = Opposite/Adjacent

__

The side DE is opposite the angle 19°, so the sine or tangent relation will be involved. The sine relation requires you know hypotenuse EF. The tangent relation requires you know adjacent side DF.

The only common side between triangles CDF and DEF is side DF. That side is opposite the given 61° angle. The given side length (CF = 24) is adjacent to the 61° angle.

This means you have enough information to use these relations:

  tan(61°) = DF/CF = DF/24

  DF = 24·tan(61°)

and

  tan(19°) = DE/DF

  DE = DF·tan(19°) = (24·tan(61°))·tan(19°) . . . . . use DF from above

  DE ≈ 24(1.804048)(0.344328) ≈ 14.908

The length of DE is about 14.91.

8 0
2 years ago
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