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2 years ago

A beach ball had a diameter of 10 inches what is the volume of air contained inside the beach ball use 3.14

Mathematics

1 answer:

TiliK225 [7]2 years ago

7 0

Answer:

10 in=

3.14=

1,570 is the LCD

Step-by-step explanation:

1. The value of a variable that makes an equation true.

2. In chemistry, a solution is a homogeneous mixture composed of only one phase.

Find the least common multiple (LCM) of the denominators in order to find the least common denominator (LCD).

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Celia sells calendars for fundraiser. Each calendar cost $9. She sells 16 calendars to her family members and 14 calendars to th

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Answer:

Since Her goal is to earn $ 300 , but now she is earning only $270 ,Hence Celia will not achieve her goal .

Step-by-step explanation:

Given as :

The cost of each calendar = $ 9

The number of calendar sold to the family = 16

The number of calendar sold to the neighborhood = 14

So, Total number of calendar sold by Celia = The number of calendar sold to the family + The number of calendar sold to the neighborhood

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3 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$