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Alina [70]
3 years ago
7

Given the numbers 9 and 6 as legs of a right triangle, what is the length of the hypotenuse? Round your answer to the nearest

Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

hypotensuse \:  =  \sqrt{  {6}^{2} +  {9}^{2} }  =  \sqrt{36 +81  }  =  \sqrt{117}  = 10.82

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Help plz!! 100 points
Fynjy0 [20]

Answer:

t = 0, 1, 4, 8

h = 0, 12, 0 , 18

Step-by-step explanation:

t = 0 + 1 + 3 + 4

/ x1 - 5 (2) x + 4x + 9

h = 0, 12, 0, 18

After 18 seconds the ball attains...

x/3 = 1/4 - 4x 2(7) = 9/2 - 2 / 4 (0)

6 0
3 years ago
Read 2 more answers
The centre of a triangle must always be found inside the triangle. Illustrate the statement with examples or deny the statement
Alla [95]

The center of a triangle must always be found inside the triangle given that it is concurrent point of the three median lines of the triangle all three of which are located only inside of the triangle

The examples of the properties of the center of a triangle are;

  1. The center of the triangle is the centroid of the triangle which is the point of concurrency of the three medians of the triangle, where a median line is the line which connects a vertex to the midpoint of the side opposite the vertex inside the triangle
  2. Each median line divides the area of the triangle in half, and given that the area of the triangle is equal to half the altitude, multiplied by the length of the base side of the triangle, the three medians of a triangle are related and share a common concurrent point <em>inside</em> the triangle such the perpendicular distance from the concurrent point of the three medians to each of the three side is less than the altitude of the triangle

Given that the three medians are located inside the triangle therefore, based on the location of the center of the triangle on the medians of the triangle, the center of the triangle must always be found inside the triangle

Learn more about the centroid of a triangle here;

brainly.com/question/16482898

3 0
3 years ago
I Need Help Please
IRISSAK [1]

Step-by-step explanation:

5 inches on the map correspond to 210 miles (or even a bit more) in reality.

we do know, the real length of the state is 213 miles.

and 8 inches to 410 (or a bit more) miles.

but, in fact, in reality, Kansas is indeed 410 miles long.

so, let's see first about the consistency of the scale factors (our ratios) in every direction.

5 inches / 210 miles = 1/42

8 inches / 410 miles = 4/205 = 1/51.25

so, in order to be a true map, both directions must have the same scale factor.

to fit the whole map on one page we must go with the smaller scale ratio : 1/51.25

so,

A with the ratio 1/1 is wrong.

B wrong.

1 cm = 1/2.54 inches

1 km = 1/1.6 miles

so, the scale ratio here is

1 cm / 1km = 1/2.54 / 1/1.6 = 1.6 / 2.54

still far off of the 1/51.25 ratio.

C with the ratio 1/10 is wrong.

D wrong

1 ft = 12 inches

the ratio is therefore

12/100 = 3/25 = 1/8.3333

still far off of the 1/51.25 ratio.

E would fit

1 cm = 1/2.54 inches

1 km = 1/1.6 miles

200 km = 200/1.6

so, the scale ratio here is

1 cm / 200km = 1/2.54 / 200/1.6 = 1.6 / (2.54×200) =

= 1.6 / 508

still far off of the 1/51.25 ratio, but in the form of being much smaller. so it fits on the page.

F would fit.

the ratio is 1/100.

this is again far off of the 1/51.25 ratio, but also in the form of being much smaller, so it fits on the page.

G would fit.

1 cm = 1/2.54 inches

1 km = 1/1.6 miles

1000 km = 1000/1.6

so, the scale ratio here is

1 cm / 1000km = 1/2.54 / 1000/1.6 = 1.6 / (2.54×1000) =

= 1.6 / 2540

again far off of the 1/51.25 ratio, but also in the form of being much smaller. so it fits on the page.

7 0
3 years ago
HELP PLEASE wil mark braniest if right
liraira [26]

Answer:

Bold or italicize to highlight important points in your answer.

Step-by-step explanation:

3 0
3 years ago
Please help me right away.
statuscvo [17]

So, with rational equations, we have three different cases. If the numerator has degree m and the denominator degree n, if m>n, the rational equation has an oblique(slant) asymptote. If m=n, the asymptote is the quotient of the leading coefficient of the numerator divided by the leading coefficient of the denominator. If m<n, the rational equation has an asymptote at 0. Since m>n in this problem, we must perform polynomial division.

\frac{x^3+2x-8}{x^2+x}= 3x-\frac{x+8}{x^2+x}

Since the remainder tends to 0 as it approaches infinity, we have a slant asymptote at y=3x.

3 0
3 years ago
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