Answer:
Yeah with that type of problem
Step-by-step explanation:
You aint getting answered for the next 4 hours <3
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer: 2d, 7, and 5f
Step-by-step explanation: Each part of the equation that is separated by a + or - is considered a "term."
A or B think it's A tho not sure
Compare this function to y=ax^2 + bx + c. You can readily see that a=2, b=0 and c=6.
The x-coord. of the vertex is at x = -b / (2a). Subbing the given values for a and b, we get
x = -(0) / (2(2) = 0. At x = 0, y = 6, so the vertex of this parabola is (0,6). It opens upward.