Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:

Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:

2. Charlene's rhombus:

Dividing the area calculated, you get:

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
solution is first os all find median
median is( 45+61)/2=53
find median of no in left of 53
it is 37
find median of no in right of 53
it is 64
now interquartile range=64-53=27
<span>Solve for each equation
h divided by 4/9 for h = 5 1/3
h 16/3
------- = -----------------
4/9 4/9
= 16/3 * 9/4
= 12
answer is </span><span>C) 12</span>