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Zarrin [17]
3 years ago
13

Penelope was reading a book at a rate

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

Penelope can read 6 pages in 5 minutes.

Step-by-step explanation:

You would use the equation 1.2x = P

P=how many pages    x=how many minutes

1.2(5) = 6

She can read 6 pages in 5 minutes

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Solve the equation –4 In(6x) = 2.<br> O A. 0.101<br> B. 0.275<br> C 3.639<br> D. 67.238
EastWind [94]

Isolate the variable using algebraic manipulation.

-4 ln(6x)=2

ln(6x)=-\frac{1}{2}

6x=e^{-\frac{1}{2}}

x=\frac{e^-\frac{1}{2}}{6}

x=0.101

Hope this helps.

頑張って!

6 0
4 years ago
Read 2 more answers
The quotient of a number and 15 plus 1
Marizza181 [45]

Answer:

x/1+15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Let h(x)=505.5+8e−0.9x . What is h(5) ? rounded to the nearest tenth. any help would be great
Naddik [55]
For this case, the first thing we are going to do is rewrite the function.
 We have then:
 h (x) = 505.5 + 8 * exp (-0.9 * x)
 We evaluate the value of x = 5 in the function.
 We have then:
 h (5) = 505.5 + 8 * exp (-0.9 * 5)
 h (5) = 505.588872
 round to the nearest tenth:
 h (5) = 505.6
 Answer:
 
the value of h (5) is:
 
h (5) = 505.6
3 0
3 years ago
Read 2 more answers
What that two numbers when multiplied give 600 and when added give 59 ​
ozzi

Answer:

Step-by-step explanation:

Let the 2 numbers be x and y

From the problem we have that

x * y = 600 and x + y = 59

From x + y = 59 -> x = 59 - y

Plug x = 59 - y to x * y = 600 we have

(59 - y) * y = 600

-> 59y - y^2 = 600

-> -y^2 + 59y - 600 = 0

-> y = (59 - \sqrt{1081})/2 or (59 + \sqrt{1081})/2

Then we could plug the answers in and find x because x = 59 - y

8 0
3 years ago
For which values of the variables the following equality is true?
Ilia_Sergeevich [38]

Answer:

For The value of a = 0 and c = 0 , The given expression equality is true  

Step-by-step explanation:

Given expression as :

\frac{3a^{2}+ac+2c-6a}{3a - c} = a - 2

Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )

Or, 3 a² + ac + 2 c - 6 a =  3 a² - ac - 6 a + 2 c

Or, (  3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0

Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0

or,  0 + 2 ac + 0

Or, 2 ac = 0

∴  a =0  and c = 0

Hence For The value of a = 0 and c = 0 , The given expression equality is true  .  Answer

6 0
3 years ago
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