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Gnesinka [82]
2 years ago
12

What is the definition of an opposite ray

Mathematics
1 answer:
kogti [31]2 years ago
5 0

Answer:

'''A ray has one endpoint and extends indefinitely in one direction. A pair of opposite rays are two rays that have the same endpoint and extend in opposite directions. Rays are always named with two points and the first point in the name must be the endpoint.'''

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xenn [34]

Answer:

They sold 60 hamburgers

Step-by-step explanation:

2 times 300 equals 600 plus 180 equals 780 hope this helps

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What is an angle that is adjacent to<br> CED?
devlian [24]
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A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
Please help me on A. B. and C.
Lunna [17]
A) fifth = 5/5 (this is a fraction) 1/5 is 1 fifth of 1. Get what i'm saying? So then the will be <u>5 fifths in a whole
</u>
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C) ok so 4 (a whole number) is 20/5 so you divide 20/5 with 2/5 (ignore this if you don't know what i'm talking about this is in middle school) so that will = <u>10</u>
4 0
3 years ago
PLEASE HELP ME I AM DESPERATE!! it’s my last j-lb question :)
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Answer:

The answer is the choice on the bottom left

Step-by-step explanation:

6 0
3 years ago
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