We are given the function <span>f(x)=sqrt of (4sinx+2) and is asked to find the first derivative of the function when x is equal to zero.
</span><span>f(x)=sqrt of (4sinx+2)
f'(x) = 0.5 </span><span>(4sinx+2) ^ -0.5 * (4cosx)
</span>f'(0) = 0.5 <span>(4sin0+2) ^ -0.5 * (4cos0)
</span>f'(0) = 0.5 <span>(0+2) ^ -0.5 * (4*1)
</span>f'(x) = 0.5 (2) ^ -0.5 * (4)
f'(x) = -.1.65
The points shown on the graph are (-1,2) and (1,-2).
d = sqrt{-2-2)^2 + (1-(-1))^2}
d = sqrt{(-4)^2 + (1+1)^2}
d = sqrt{16 + 4}
d = sqrt{20}
d = 4•sqrt{5}
d is about 8.94427191.
Rounded to the nearest tenth, we get d = 8.9.
600,000 is 60 ten thousandths
Answer: D+Q= 30
0.10 d+ 0.25 q= 4.80
Step-by-step explanation:
A dime is worth 10 cents and a quarter is worth 25 cents.
Answer:
4. 40°
5. 15
6.
I hope this helps. I don't know the last one.
