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3 years ago

The length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle

1 answer:

8 0

The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
p = 2l + 2w
2w = p - 2l
w = (p - 2l)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in

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In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.

Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

AO = x - 1

CO = BO = x + 1

OD = x + 4

Now,

$\rm In \: \triangle \: AOB \: and \: \triangle \: COD$

$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

$\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}$

$\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}$

$\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}$

$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

$\rm \longmapsto\: 3x - 4 = 1 + 2x$

$\rm \longmapsto\: 3x - 2x= 1 +4$

$\bf\longmapsto \:x = 5$

7 0

2 years ago

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Sergio [31]

Answer:

Step-by-step explanation:

it is 6/6

if it is right brainliest pls thanks

6 0

2 years ago

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In the equation 5x-2=-x-20, What is the value of x? a. 2 b. -1 c. -3 d. -2

mestny [16]

Answer:

C choice.

Step-by-step explanation:

$5x - 2 = - x - 20 \\$

First, we move the same terms to the same side.

$5x + x = - 20 + 2 \\ 6x = - 18$

Then we move 6 to divide - 18.

$x = \frac{ - 18}{6} \\ x = - 3$

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2 years ago

7.9 - 4.012. I really don't know the answer

Lunna [17]

3.888 :))))))))))))))))))))))))))

7 0

3 years ago

Problem Page Ann will run more than 38 miles this week. So far, she has run 21 miles. What are the possible numbers of additiona

krok68 [10]

She has run 21 miles already. Let t be the number of additional miles added on.

In total, she has run t+21 miles

This is going to be set greater than 38 since "Ann will run more than 38 miles"

So we have this inequality

t+21 > 38

we solve for t by subtracting 21 from both sides

t+21 > 38
t+21-21 > 38-21
t+0 > 17
t > 17

The final answer is t > 17

which means that the possible additional number of miles she could run is anything larger than 17. So t = 18 is one possibility.

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3 years ago