Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
18
Step-by-step explanation:
1gchdafvh
Dudyr
Wybk D
Answer:
B
Step-by-step explanation:
50+55+48+50+52=255
255/5=51
Anwser 51
Answer:
-3.85
-3 is a whole number, it comes before the decimal point.
17/20 is a fraction so it goes on the other side.
Answer:
190.1, 101.89, 101.9, 100.789, 112, 1
Step-by-step explanation:
