Answer:
19.5 because if we do hundred then it well equal to 19.5
Answer:
The Proof is below.
Step-by-step explanation:
Given:
![\overline {ML} \cong \overline{MN}](https://tex.z-dn.net/?f=%5Coverline%20%7BML%7D%20%5Ccong%20%5Coverline%7BMN%7D)
To Prove:
![\overline {LQ} \cong \overline{QN}](https://tex.z-dn.net/?f=%5Coverline%20%7BLQ%7D%20%5Ccong%20%5Coverline%7BQN%7D)
Proof:
In ΔLPM and ΔNPM
……….{Given}
……….{Given}
……….{Reflexive Property}
ΔLPM ≅ ΔNPM ….{ By Side-Side-Side congruence test}
∴ ∠LMP ≅ ∠NMP ...{Corresponding parts of congruent triangles (c.p.c.t).}.....( 1 )
Now In ΔLMQ and ΔNMQ
……….{Given}
∠LMQ ≅ ∠NMQ ..........{From 1 above}
……….{Reflexive Property}
ΔLMQ ≅ ΔNMQ ....{ By Side-Angle-Side Congruence test}
∴
...{Corresponding parts of congruent triangles (c.p.c.t).}.....Proved
Hello Austint1414
The answer in standard form would be <u><em>70,633,999,564,087,001</em></u>
:)
Answer:
x ---- y
1 ---- 3
4 ---- 12
6 ---- 18
Step-by-step explanation:
Given
![y = 3x](https://tex.z-dn.net/?f=y%20%3D%203x)
Required
Create a table that represents this scenario
Because x represents time, x can not be negative. So, the domain of x is:
![x \geq 0](https://tex.z-dn.net/?f=x%20%5Cgeq%200)
Assume ![x = 1](https://tex.z-dn.net/?f=x%20%3D%201)
![y = 3 * 1 = 3](https://tex.z-dn.net/?f=y%20%3D%203%20%2A%201%20%3D%203)
Assume x = 4
![y=3*4 = 12](https://tex.z-dn.net/?f=y%3D3%2A4%20%3D%2012)
Assume x = 6
![y=3*6 = 18](https://tex.z-dn.net/?f=y%3D3%2A6%20%3D%2018)
Hence, the table is:
x ---- y
1 ---- 3
4 ---- 12
6 ---- 18
Answer:
1
Step-by-step explanation:
2/4 + 1/2 = 1
Hope this helps you!