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Oliga [24]
3 years ago
10

maria brought a blouse on sale for 20% off. the sale price was $21.76. what was the original price? round to the nearest hundred

th.
Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer: $27.20

Step-by-step explanation:

She bought a blouse for 20% off so it means that she paid 80% of the original price.We can then set up the equation  

80% of x = 21.76   where x is the original price so solve for x

0.8x = 21.76  

x = 27.20

Which  means the original price is $27.20

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A racecar travels 225 miles per hour. How far will it drive in 6 1/2 hours?
saul85 [17]

Answer:

1462.5

Step-by-step explanation

225 mph means of course 225 miles per hour

225 x 6 is 1350 and then you have to do 225/2 which is 112.5 to find what half of 225 is then you add 1350+112.5 to get 1462.5

8 0
2 years ago
Read 2 more answers
Solve:<br> -11 - 79 +5g = 3
Katyanochek1 [597]

Answer:

g=18.6

Step-by-step explanation:

-11-79+5g=3

-90+5g=3

5g=3+90

5g=93

g=93/5=18.6

g=18.6

6 0
3 years ago
(b) As in part (a), how many three-digit phone prefixes are possible that do not start with 0 or 1, but contain 0 or 1 as the mi
Lubov Fominskaja [6]

Answer:

The number of 3-digit phone prefixes that do not start with 0 or 1, but contain 0 or 1 as the middle digit is 160.

Step-by-step explanation:

The phone prefix for any area is of the form <u>X</u> <u>X</u> <u>X</u>.

These prefixes can take values from 0 to 9.

The condition to create a phone prefix is:

  • The first digit cannot be 0 or 1
  • The middle digit is either 0 or 1.

The possible number of ways to fill the first place is 8 since 0 or 1 cannot be the first digit.

The possible number of ways to fill the second place is 2 since the middle digit can be occupied by either 0 or 1.

The possible number of ways to fill the last place is 10 since there are no condition applied to the last digit.

Then the number of phone prefixes that can be formed is = 8\times2\times10=160

Thus, the possible number of phone prefixes possible is 160.

7 0
3 years ago
In a class of 20 students:
Artyom0805 [142]

Whats the question? I dont understand whats happenign here.

5 0
2 years ago
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Simplify:
OverLord2011 [107]

Step-by-step explanation:

Simplify :

x4−6x3+2x−7+7x3−x+5x2+2−x4

x4−6x3+2x−7+7x3−x+5x2+2−x4

Rearranging and collecting the like terms, we get:

=(x4−x4)+(−6x3+7x3)+5x2+(2x−x)+(−7+2)

=(1−1)x4+(−6+7)x3+5x2+(2−1)x+(−7+2)

=(1)x3+5x2+(1)x−7+2

=x3+5x2+x−5

8 0
3 years ago
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